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(250)(x^2)-15x-3=0=
a = 250; b = -15; c = -3;
Δ = b2-4ac
Δ = -152-4·250·(-3)
Δ = 3225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3225}=\sqrt{25*129}=\sqrt{25}*\sqrt{129}=5\sqrt{129}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5\sqrt{129}}{2*250}=\frac{15-5\sqrt{129}}{500} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5\sqrt{129}}{2*250}=\frac{15+5\sqrt{129}}{500} $
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